使用DW用ASP ACCESS编写目录树
时间:2007-12-23 来源:不详 作者:迈克DB
document.MM_pgW=innerWidth; document.MM_pgH=innerHeight; onresize=MM_reloadPage; }}
else if (innerWidth!=document.MM_pgW || innerHeight!=document.MM_pgH) location.reload();
}
MM_reloadPage(true);
//-->
</script>
<script language="JScript">
<!-- //此函数设置处理表单的内容
//比如添加时，表单为空，并显示为什么节点添加子节点
//比如修改时，表单内为相应节点的内容，并显示在修改什么节点
function showForm(disp,parentId){
addNodeDiv.style.display="";
document.all.addNodeForm.disp.value=disp;
document.all.addNodeForm.parentId.value=parentId;
if(disp=="edit"){
document.all.addNodeForm.listInfo.value=eval("img" parentId ".alt");
document.all.addNodeForm.listName.value=eval("listName" parentId ".innerText");
infoValue.innerText="编辑[" eval("listName" parentId ".innerText") "]节点";
}
else{ 内容来自dedecms
document.all.addNodeForm.listInfo.value="";
document.all.addNodeForm.listName.value="";
infoValue.innerText="给节点[" eval("listName" parentId ".innerText") "]添加子节点";
}
}
<!--这棕色部分为移动表单代码，可以不要。//-->
function MM_findObj(n, d) { //v4.01
var p,i,x; if(!d) d=document; if((p=n.indexOf("?"))>0&&parent.frames.length) {
d=parent.frames[n.substring(p 1)].document; n=n.substring(0,p);}
if(!(x=d[n])&&d.all) x=d.all[n]; for (i=0;!x&&i<d.forms.length;i ) x=d.forms[i][n];
for(i=0;!x&&d.layers&&i<d.layers.length;i ) x=MM_findObj(n,d.layers[i].document);
if(!x && d.getElementById) x=d.getElementById(n); return x;
} function MM_dragLayer(objName,x,hL,hT,hW,hH,toFront,dropBack,cU,cD,cL,cR,targL,targT,tol,dropJS,et,dragJS) { //v4.01
//Copyright 1998 Macromedia, Inc. All rights reserved.
本文来自织梦
var i,j,aLayer,retVal,curDrag=null,curLeft,curTop,IE=document.all,NS4=document.layers;
var NS6=(!IE&&document.getElementById), NS=(NS4||NS6); if (!IE && !NS) return false;
retVal = true; if(IE && event) event.returnValue = true;
if (MM_dragLayer.arguments.length > 1) {
curDrag = MM_findObj(objName); if (!curDrag) return false;
if (!document.allLayers) { document.allLayers = new Array();
with (document) if (NS4) { for (i=0; i<layers.length; i ) allLayers[i]=layers[i];
for (i=0; i<allLayers.length; i ) if (allLayers[i].document && allLayers[i].document.layers)
with (allLayers[i].document) for (j=0; j<layers.length; j ) allLayers[allLayers.length]=layers[j];
} else {
if (NS6) { var spns = getElementsByTagName("span"); var all = getElementsByTagName("div");
for (i=0;i<spns.length;i ) if (spns[i].style&&spns[i].style.position) allLayers[allLayers.length]=spns[i];}
文章评论
共有位Admini5网友发表了评论 查看完整内容